const menuKind = this.props.dispatch<any>(resourceUuidToContextMenuKind(resourceUuid));
if (menuKind && resource) {
this.props.dispatch<any>(openContextMenu(event, {
- name: '',
+ name: resource.name,
uuid: resource.uuid,
+ description: resource.description,
ownerUuid: resource.ownerUuid,
isTrashed: ('isTrashed' in resource) ? resource.isTrashed: false,
kind: resource.kind,